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\title{å½“å¤©é’beamerä¸»é¢˜æ‹¿æ¥åšæµ·æŠ¥}
\author{ä½œè€…ç”²ã€ä½œè€…ä¹™ã€ä½œè€…ä¸™}

\begin{document}

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        \item æœ¬æ¥è¿™ä¸ªbeamerä¸»é¢˜æ&nbsp;·å¼ï¼Œæƒ³å–åâ€œé’èŠ±ç“·â€çš„ã€‚ä¸è¿‡å§‹ç»ˆæ²¡èƒ½åŠ›é‡çŽ°å‡ºæ¥é‚£ç§æ„Ÿè§‰å•¦ï¼Œå°±ç®—äº†ã€‚
        \item è¯è¯´æ‹¿è¿™ä¸ªæ¨¡æ¿åŽ»åšç§‘ç&nbsp;”å­¦æœ¯æ€§æŠ¥å‘Šï¼ŒçœŸçš„ä¸ä¼šè¢«å¯¼å¸ˆä¸¢å‡ºæ¥å—ã€‚
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    \begin{exampleblock}{ç®—äº†æˆ‘ä¹Ÿä¸çŸ¥é“åœ¨å†™ä»€ä¹ˆï¼Œdo you?}
        Now solve $x = \frac{-b \pm \sqrt{b^2 -4ac}}{2a}$. å¯¹å„ä½åŒå­¦æ¥è¯´åº”è¯¥æŒ‘æˆ˜ä¸å¤§ã€‚
    \end{exampleblock}
    
    \begin{alertblock}{ç®—äº†æˆ‘ä¹Ÿä¸çŸ¥é“åœ¨å†™ä»€ä¹ˆï¼Œdo you?}
        \[ x = \frac{-b \pm \sqrt{b^2 -4ac}}{2a} \]
    \end{alertblock}
    
    \begin{block}{ç®—äº†æˆ‘ä¹Ÿä¸çŸ¥é“åœ¨å†™ä»€ä¹ˆï¼Œdo you?}
        \[ x = \frac{-b \pm \sqrt{b^2 -4ac}}{2a} \]
    \end{block}
    
    \begin{proof}
        æ˜¾è€Œæ˜“è§ï¼Œ$1+1=2$.
    \end{proof}
    
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\begin{block}{\ch{SiO2}ä¸Ž\ch{Al2O3}å—çƒ­å˜åŒ–è¿‡ç¨‹ \cite{ShaoShen2022}}
    \Large\centering
\ch{!(é«˜å²­çŸ³)( Al2O3*2 SiO2*2 H2O ) -&gt;[è„±æ°´] !(åé«˜å²­çŸ³)( Al2O3 * 2 SiO2 ) -&gt;[åŠ&nbsp;çƒ­] !(ç¡…é“å°–æ™¶çŸ³)( 2 Al2O3 * 3 SiO2 ) -&gt;[åŠ&nbsp;çƒ­] !(èŽ«æ¥çŸ³)( 3 Al2O3 * 2 SiO2 )}
\end{block}

\begin{block}{äºŒæ°§åŒ–ç¡…ç»“æž„åŠå­˜åœ¨å½¢æ€\cite{ShaoShen2022}}
\centering
\includegraphics[width=.8\textwidth]{SiO2}\par
(1) äºŒæ°§åŒ–ç¡…(SiO2)ç»“æž„ï¼›(2) ç»“æ™¶äºŒæ°§åŒ–ç¡…ï¼›(3) æ—&nbsp;å®šå½¢äºŒæ°§åŒ–ç¡…
\end{block}

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